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2 years ago

Which answer would it be

Mathematics

2 answers:

lawyer [7]2 years ago

7 0

Answer:

is your screen ok???

Step-by-step explanation:

ziro4ka [17]2 years ago

5 0

Answer:

Step-by-step explanation:

usually anything with 11 on the numerator is a repeating decimal and the 0.37 is closest to 36.

so by guessing you know is D

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Line F passes through the points (7, 13) and (9, -3). What is the slope of a line parallel to line F?

madreJ [45]

13+3/7-9
16/-2
-8
A) -8

6 0

2 years ago

What is the completely factored form of f(x)=x^3-7x^2+2x+4

xxMikexx [17]

$Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)$

$Steps:$

$x^3-7x^2+2x+4$

$Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}$

$\frac{x^3-7x^2+2x+4}{x-1}$

$\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}$

$\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}$

$\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4$

$\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

8 0

2 years ago

PLEASE!!!!! HELP ME!!!!!!

kati45 [8]

Answer:

$15 = a_1 r^4$ (1)

$1 = a_1 r^5$ (2)

If we divide equations (2) and (1) we got:

$\frac{r^5}{r^4}= \frac{1}{15}$

And then $r= \frac{1}{15}$

And then we can find the value $a_1$ and we got from equation (1)

$a_1 = \frac{15}{r^4} = \frac{15}{(\frac{1}{15})^4} =759375$

And then the general term for the sequence would be given by:

$a_n = 759375 (\frac{1}{15})^n-1 , n=1,2,3,4,...$

And the best option would be:

C) a1=759,375; an=an−1⋅(1/15)

Step-by-step explanation:

the general formula for a geometric sequence is given by:

$a_n = a_1 r^{n-1}$

For this case we know that $a_5 = 15, a_6 = 1$

Then we have the following conditions:

$15 = a_1 r^4$ (1)

$1 = a_1 r^5$ (2)

If we divide equations (2) and (1) we got:

$\frac{r^5}{r^4}= \frac{1}{15}$

And then $r= \frac{1}{15}$

And then we can find the value $a_1$ and we got from equation (1)

$a_1 = \frac{15}{r^4} = \frac{15}{(\frac{1}{15})^4} =759375$

And then the general term for the sequence would be given by:

$a_n = 759375 (\frac{1}{15})^n-1 , n=1,2,3,4,...$

And the best option would be:

C) a1=759,375; an=an−1⋅(1/15)

4 0

3 years ago

Need help asap. it's from the iready diagnostic.

mariarad [96]

Answer:

Darn I had one of those a few weeks ago, I'm so sorry if I'm wrong but I think it's option 3? I'd wait for someone else to answer though just it case I'm wrong. God bless!

6 0

2 years ago

Find f(h(-1))<br> 2<br> -9<br> 11<br> -11

kumpel [21]

Answer:

(d) -11

Step-by-step explanation:

Each of the functions is evaluated in the usual way: put the number where the variable is in the expression and simplify.

h(-1) = -2(-1)² -3(-1) +1 = -2 +3 +1 = 2

f(2) = (2(2) +7)/(2 -3) = 11/-1 = -11

Then f(h(-1)) is ...

f(h(-1)) = f(2) = -11

5 0

1 year ago