How many zeros does the function f(x)=3x^12 -17x^8+11x^4-6x+23 have

Mathematics

1 answer:

jeyben [28]2 years ago

5 0

Answer:

12.

Step-by-step explanation:

The number of zeros to an equation is the highest power of the polynomial.

A quadratic equation whose highest degree is 2, has two solutions.

The equation f(x) = $3x^{12} - 17x^{8} + 11x^{4} - 6x + 23$ will have 12 solutions (or zeroes) since the highest degree is 12.

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