Add 7.2 each time until you get to 102
List all the different combinations with total cost:
Airplane + van = 350 + 60 = $410
Airplane + cab = 350 + 40 = $390
Bus + van = 150 + 60 = $210
Bus + cab = 150 + 40 = $190
Train + van = 225 + 60 = $285
Train + cab = 225 + 40 = $265
There are 6 different combinations.
There are 2 that are more than $300
The probability would be quantity higher than 300 / total combinations.
Probability = 2/6 = 1/3
Answer:
2, 2, 3, 5, 7 that is the farthest you can go
Step-by-step explanation:
2,2,3,5,7 prime factorization of 420 but impossible to get 9 factors
Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)