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3 years ago

Graph the solution of this inequality 3/7(35x-14)<_21x/2+3

Mathematics

1 answer:

Aleks [24]3 years ago

5 0

Wolphramalpha.com will help you tons

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How do you do this question?

Step2247 [10]

Answer:

Step-by-step explanation:

$f(x)=(x-1)(x^2+2)^3\\f'(x)=(x-1)*3(x^2+2)^2*2x+(x^2+2)^3*1\\f'(x)=6x(x-1)(x^2+2)^2+(x^2+2)^3\\f'(x)=(x^2+2)^2[6x^2-6x+x^2+2]\\f'(x)=(x^2+2)^2(7x^2-6x+2)\\D$

7 0

2 years ago

The distance to the grocery store is<br> 13.456 miles. Round this distance to<br> the nearest tenth,

Jobisdone [24]

Answer:

13.5

Step-by-step explanation:

Round the .45 to .5

7 0

2 years ago

Read 2 more answers

In the western region about many more l200 models were sold than l100 models?

LenKa [72]

I think about 100 models

5 0

2 years ago

What is 2x-6x please I need help.

cupoosta [38]

Answer:

Step-by-step explanation:

5 0

2 years ago

Using the data in the table, use the exponential smoothing method with alpha=0.5 and a February forecast of 500 to forecast

Sever21 [200]

Answer:

Step-by-step explanation:

The formula to calculate the forecast could be determine by using the exponential smoothing method :

$Ft = F(t-1) + \alpha [A(t-1) - F(t-1)]$

Where ,Ft is the Forecast for period t

F(t-1) is the Forecast for the period previous to t

A(t-1) is the Actual demand for the period previous to t

$\alpha$ = Smoothing constant

To get the forecast for may and june the above formula with $\alpha =0.5$ and april forecast of 500 will be used

For march

$=500+0.5(520-500)\\\\=500+0.5\times20\\\\=500+10\\\\=510$

For April

$=510+0.5(535-510)\\\\=510+0.5\times25\\\\=510+12.5\\\\=522.5$

For May

$=522.5+0.5(550-5225)\\\\=522.5+0.5\times27.5\\\\=522.5+13.75\\\\=536.25$

So forecast for May = 536.25

6 0

3 years ago