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3 years ago

Please assist in solving the system of equation please and thank you

Mathematics

1 answer:

morpeh [17]3 years ago

8 0

Okay so how you solve an equation is listed here:
hmm lets say 4x + 1 ÷2= 6

4x + 1 ~÷2~= 6
~x2~ x2
------------------------
4x~+1~ 12
~ -1~ -1
-------------------------
4x. 11
÷4. ÷4
-----------------------
x. = 2.75

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At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

What is 20% of 30% of 40% of $50

GarryVolchara [31]

20% of $50 = $10

30% of $50 = $15

40% of $50 = $20

Multiply 20% by $50

30% by $50

40% by %50

6 0

3 years ago

Help I need to know how to solve for x

lara [203]

Answer:

the answer would be x=3

Step-by-step explanation:

the lines the have 1 line across it equal the same. same for the ones with 2. for example AB has one line across so it also equals CD because it has one line across (in the little octagonal shape). BC has two lines and so does AH so BC=AH

3 0

3 years ago

Given that f(x) =<br> X + 3/2<br> a) Find f(2)<br> b) Find f^-1(x)<br> c) Find f^-1(12)

zysi [14]

A) x+3/2
b) x/f
c) 12/f

Mark brainliest please

Hope this helps you

5 0

2 years ago

What letter is s in 8s=1/2

Tcecarenko [31]

We find the value for s here.

8s = 1/2
$8s = \frac{1}{2} 
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8s/8 = \frac{1}{2} / \frac{8}{1} 

$

1/2 divided by 8/1 = 1/2 * 1/8 = 1/16

s = 1/16

7 0

2 years ago