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2 years ago

Which set dose - 4/9 belong A integers B whole numbers C natural numbers D rational numbers

Mathematics

2 answers:

slava [35]2 years ago

5 0

Answer

4/9 belongs to rational numbers (D).

Explanation

(Lol moderator deleted everyone's answers so I'm gonna answer).

First I'll give you a definition of each choice.

Integers: Integers don't include decimals or fractions. Integers are positive and negative numbers. So basically it's this; (..., -3, -2, -1, 0, 1, 2, 3, ...). The '...' means numbers from infinity to the next number. I hope this makes sense Imao.

Whole numbers: whole numbers are integers, except they don't include negative numbers. Whole numbers include 0 (zero)... (0, 1, 2, 3, ...)

Natural numbers: natural numbers are whole numbers but they don't include 0 (zero)... (1, 2, 3, ...)

Rational numbers: rational numbers are numbers that can be expressed as a fraction. This includes repeating decimals such as 0.333 repeating. Rational numbers also include integers, because if you put the number over one, that is a fraction. Rational numbers are basically every number except for the radicals of some numbers (such as the square root of 3) and pi.

So now let's just see which one 4/9 is.

Well, 4/9 is not an integer, whole number, or natural number because it is a fraction.

But 4/9 can be expressed as a fraction (well, it already is one) meaning it is a rational number.

Mrac [35]2 years ago

4 0

Answer:

-4/9 is a rational number

Step-by-step explanation:

Rational numbers are the numbers you can make by dividing one integer by another, so in other words a fraction.

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Expand (4x-2y)^3 for math final

lisov135 [29]

In general: (a - b)^3 = a^3 - 3 a^2b + 3 a b^2 - b^3
(4x-2y)^3 = (4x)^3 - 3 (4x)^2(2y) + 3 (4x) (2y)^2 - (2y)^3

5 0

3 years ago

B - 1 > -17 what does b equal?

Nastasia [14]

Answer:

b > -16

Step-by-step explanation:

The inequality is given as:

b - 1 > -17

To solve this problem, add +1 to both sides of the expression:

b - 1 + 1 > -17 + 1

Now;

b > -16

So, all values for which b is more than -16 satisfy the solution for this problem.

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3 years ago

the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai

Blababa [14]

Let $X$ be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

$P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10$

where $Z$ follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

$P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)$

where $F_Z(z)=P(Z\le z)$ denotes the CDF of $Z$ , and $F_Z^{-1}$ denotes the inverse CDF. We have

$z_1=F_Z^{-1}(0.90)\approx1.2816$

Similarly, because 20% of students obtain less than 40 marks, we have

$P(X$

so that

$P(Z$

Then $\mu,\sigma$ are such that

$\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma$

$\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma$

and we find

$\mu\approx53.8739,\sigma\approx16.4848$

3 0

4 years ago

One of ten different prizes was randomly put into each box of a cereal. If a family decided to buy this cereal until it obtained

Reptile [31]

Answer:

29.29

Step-by-step explanation:

The first trial among a distribution of independent trials with a constant success probability follows a geometric probability.

The expected value of a negative binomial is the reciprocal of its success probability p.

E(X)=1/p

At the first draw, we only selected one of the 10 prizes and so 1 draw gives a success

E(X)=1/p

E(X1)=1

After the first prize is drawn, we are interested in the first time (success), that we draw another prize that is different (p=9/10)

E(X2)=1/9÷10

E(X2)= 10/9

After the first prizes have being drawn, we now interested in the first time success that we draw a different prize from the first 2

E(X3)=1/8÷10

E(X3)=10/8

E(X3)=5/4

After the first three prizes have been drawn, we are now interested in the success of a first time draw for the 4th different prize

E(X4)=1/7÷10

E(X4)=10/7

Fifth different prize

E(X5)=1/6÷10

E(X5)=10/6

E(X5)=5/3

Sixth different prize

E(X6)=1/5÷10

E(X6)=10/5

E(X6)=2

Seventh different prize

E(X7)=1/4÷10

E(X7)=10/4

E(X7)=5/2

Eighth different prize

E(X8)=1/3÷10

E(X8)=10/3

Ninth different prize

E(X9)=1/2÷10

E(X9)=10/2

E(X9)=5

After the 9 different prizes have been drawn, we are interested in the first time we will draw the tenth different prize

E(X10)=1/1÷10

E(X10)=10

Add up all corresponding values;

E(X)=E(X1)+E(X2)+E(X3)+E(X4)+E(X5)+E(X6)+E(X7)+E(X8)+E(X9)+E(X10)

E(X)=1+10/9+5/4+10/7+5/3+2+5/2+10/3+5+10

E(X)= 29.29

Note: Those values in E(X), should be written the way it will in standard algebra ie they should be small.

4 0

3 years ago

Order the following numbers from greatest to least: 7.321, 7.3, 7.065, 7.65

Slav-nsk [51]

The order for the given decimal numbers, from the greatest to the least, is: D. 7.65, 7.321, 7.3, 7.065.

<h3>How to Order a Set of Decimal Numbers?</h3>

When considering the order of a set of decimal numbers, the value larger the digit that is close to the decimal point, the larger the decimal number, and vice versa.

Given the following set of decimal numbers, 7.321, 7.3, 7.065, 7.65.

Notice that all decimal numbers start with 7. So, the digit close to the decimal point is what we will consider to determine which decimal number is greater or the least.

The decimal number that has the greater digit that is close to the decimal point is, 7.65, followed by 7.321, then 7.3.

The decimal number with the least digit closer to the decimal point is 7.065.

Therefore, the order for the given decimal numbers, from the greatest to the least, is: D. 7.65, 7.321, 7.3, 7.065.

Learn more about order of decimal numbers on:

brainly.com/question/20603315

#SPJ1

6 0

2 years ago

Which set dose - 4/9 belong A integers B whole numbers C natural numbers D rational numbers​

Which set dose - 4/9 belong A integers B whole numbers C natural numbers D rational numbers