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2 years ago

Roxanna has a collection of silver spoons from all over the world.

Mathematics

1 answer:

Vikentia [17]2 years ago

6 0

50 because spoons 15 so desk 14 seat 10

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What’s the correct graph ?

maks197457 [2]

Answer:

The correct graph is graph E.

Step-by-step explanation:

We can tell this because we know the graph must stay below 3. So any graph over 3 gets thrown out. We also know that it must not go further down than -3. This is because any number over -3 as an input, when taking an absolute value, would be greater than 3.

Graph E shows numbers that are all less than 3 and greater than -3.

8 0

3 years ago

Ya yeet answer dis plzz

NNADVOKAT [17]

He would keep 3/8 for himself. Hope it helps! :)

7 0

3 years ago

Read 2 more answers

Which set of ordered pairs represents a linear function?

kifflom [539]

Answer:its d

Step-by-step explanation:

3 0

3 years ago

Graph and label the image of the figure below after a dilation by a factor of 1/2.

neonofarm [45]

Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

$\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\ \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\ \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}$ $\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\ \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}$

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0

9 months ago

PLZ HELP ME

Likurg_2 [28]

Answer:

x ≈ 14.87

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² = 10² + 11² = 100 + 121 = 221 ( take the square root of both sides )

x = $\sqrt{221}$ ≈ 14.87 ( to the nearest hundredth )

8 0

2 years ago