Scale for y - 1:1
Scale for x - 1:10
Reason- so that i can plot the points on the graph without any modification to the given one.
Now plot the points on the graph using the scale. I cant obviously do that here.
Answer:
ggtr
Step-by-step explanation:
GIMME THOSE POINTS
Answer:
7x-6
Step-by-step explanation:
2(4x-5)-(x-4)
8x-10-x-(-4)
8x-10-x+4
7x-10+4
7x-6
the 2 equations given are vertical angles which mean they would equal the same.
Set the two equations to equal each other to solve for x:
6(x-2) = 3x+30
Simplify the left side:
6x-12 = 3x+30
Add 12 to eac side:
6x = 3x+42
Subtract 3x from each side"
3x = 42
Divide both sides by 3:
X = 42/3
X = 14
Now you know X, replace x with 14 in the equation for DHG:
DHG = 6(x-2)
6(14-2)
Simplify:
6(12)
Multiply:
72
Angle DHG is 72 degrees.
Answer:
160 cubic centimeters
Step-by-step explanation:
step 1
Find the scale factor
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
Let
z ---> the scale factor
----> the ratio of corresponding radii
simplify
![z=\frac{2}{3}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B2%7D%7B3%7D)
step 2
Find the volume of the smaller cone
we know that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z ---> the scale factor
x ----> the volume of the smaller cone
y ---> the volume of the larger cone
![z^{3}=\frac{x}{y}](https://tex.z-dn.net/?f=z%5E%7B3%7D%3D%5Cfrac%7Bx%7D%7By%7D)
we have
![z=\frac{2}{3}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B2%7D%7B3%7D)
![y=540\ cm^3](https://tex.z-dn.net/?f=y%3D540%5C%20cm%5E3)
substitute
![(\frac{2}{3})^{3}=\frac{x}{540}](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B3%7D%29%5E%7B3%7D%3D%5Cfrac%7Bx%7D%7B540%7D)
![x=540(\frac{2}{3})^{3}](https://tex.z-dn.net/?f=x%3D540%28%5Cfrac%7B2%7D%7B3%7D%29%5E%7B3%7D)
![x=160\ cm^3](https://tex.z-dn.net/?f=x%3D160%5C%20cm%5E3)