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matrenka [14]
3 years ago
13

What’s the answer for #11 @HavannaS? Spent 20 min and clueless, thank you!!!!!!

Mathematics
1 answer:
Elis [28]3 years ago
8 0
Angle 2=3, so angle 1=4 because angles ABC & BCD equal 90°. When you add together the angles of a triangle you get 180 and if you could put angle 1 and 4 together it would look like an upward version.



That is the best way I could describe it. Hope that helps.
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Units used to describe volume are cubic
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Write the percent as a fraction in simplest form 50%
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1/2

Step-by-step explanation:

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Simplify 3^8 x 3^4 / 3^2 x 3^8 leaving your answer in index form
Furkat [3]

Answer:

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Step-by-step explanation:

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\frac{3^{12}}{3^{10}}

Step 2: Subtract exponents

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2 years ago
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A house was valued at $100,000 in the year 1987. The value appreciated to $165,000 by the year 2002.
iris [78.8K]

Answer:

  A) The annual multiplier was 1.0339; the annual increase was 0.0339 of the value.

  B) 3.39% per year

  C) $182,000

Step-by-step explanation:

A) Let's let t represent years since 1987. Then we can fill in the numbers and solve for r.

  165000 = 100000(1 +r)^15

  1.65^(1/15) = 1 +r . . . . . divide by 100,000; take the 15th root

  1.03394855265 -1 = r ≈ 0.0339

The value was multiplied by about 1.0339 each year.

__

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8 0
3 years ago
Work out the size of one of the exterior angles
hodyreva [135]

<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>

⠀

  • A polygon with 10 sides ( Decagon )

⠀

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

⠀

  • The value of one of the exterior angles

⠀

<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

\qquad \diamond \:  \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \:  \star

⠀

<u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

Putting the given values, we get,

⠀

\sf \dashrightarrow Exterior ~angle =  \dfrac{360  ^\circ}{10} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \frac{36 \cancel{0}^\circ}{ \cancel{10}} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\  \\

Thus, the value of the exterior angles of a Decagon is 36°.

⠀

\underline{ \rule{227pt}{2pt}} \\  \\

8 0
2 years ago
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