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3 years ago

3/5, 1/3 common denominator

Mathematics

2 answers:

4vir4ik [10]3 years ago

7 0

3/5*3/3=9/15
1/3*5/5=5/15
15 is a common denominator.

nordsb [41]3 years ago

5 0

15. Just check it lol, if you keep on adding 3 as you are adding 5 to the other denominator, both numbers will eventually reach 15.

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Dion practiced the long jump . He jumped 3.05 meters,2.74 meters and 3.3 meters.What was the average length of Dion's jumps?

Mademuasel [1]

All you do is subtract 3.05 and 2.74 then do the same thing with the other ones and see what number is between all of them. What grade are you in

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3 years ago

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PLEASE HELP QUICK, I need to know the answer.

Marysya12 [62]

The equivalent expression is $7^{2}$ .

We have the following expression -

$\frac{7^{-3} }{7^{-5} }$

We have to find its equivalent value.

<h3>What is the equivalent expression of the following expression-</h3>

$f(x, y) =\frac{A^{x} }{A^{y} }$

In order to divide two exponents with same base, we use the 'Quotient property of exponents.

The equivalent expression can be written as -

f(x, y) = $A^{x} A^{-y} = A^{x-y}$

In the question given we have -

$\frac{7^{-3} }{7^{-5} }$

Using the property discussed above -

$7^{-3}\;7^{5}$ = $7^{-3+5}$ = $7^{2}$

Hence, the equivalent expression is $7^{2}$ .

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brainly.com/question/17173276

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2 years ago

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The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how

vichka [17]

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$

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3 years ago

Is the point (5,-1) a solution of y=2x-11

Nataly [62]

if the given point satisfies this equation then it would be its solution

(-1)=2(5)-11

-1=10-1

-1=-1

lHS=RHS

Hence (/,-1) is the solution of y=2x-11

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3 years ago

5.7kg in grams convert

dimaraw [331]

Answer:

5700 grams

Step-by-step explanation:

1 kg = 1000 grams

5.7 kg = 5.7 × 1000

=> 5700 grams

hope it helps!

5 0

3 years ago