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Rom4ik [11]
3 years ago
5

3/5, 1/3 common denominator

Mathematics
2 answers:
4vir4ik [10]3 years ago
7 0
3/5*3/3=9/15
1/3*5/5=5/15
15 is a common denominator.
nordsb [41]3 years ago
5 0
15. Just check it lol, if you keep on adding 3 as you are adding 5 to the other denominator, both numbers will eventually reach 15.
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Translate the following phrase into an expression:The difference between 20 and twice of a number twice of a number
Vitek1552 [10]

Answer: probably D

In math difference means subtraction

Step-by-step explanation:

7 0
3 years ago
In which step does a mistake first occur? please help!
Leya [2.2K]

Answer:

step 1

Step-by-step explanation:

8÷2+(3x3-2)

8÷2+(9-2)

8÷2+(7)

4+7

=11

3 0
2 years ago
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The product of two numbers is -30, but their sum is -13. What are these two numbers?
Nata [24]
<h3>Answer:  -15 and 2</h3>

You find this through trial and error.

A much more efficient way is to solve x^2-13x-30 = 0 using the quadratic formula. You'll find the two solutions to be x = 15 and x = -2

Going from those solutions, we get x-15 = 0 and x+2 = 0 which then turn into (x-15)(x+2) = 0 through the zero product property.

3 0
3 years ago
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Help based offf order of operations please help
JulijaS [17]

Answer:

The answer for :

h. \:  \:   \: \frac{5}{6}

i. \:  \:  \:  \frac{35}{32}

k. \:  \:  \:  \frac{-29}{20}

l. \:  \:  \:  \frac{13}{15}

Step-by-step explanation:

Question h:

\frac{2}{3}  + ( \frac{1}{3}  \times  \frac{1}{2} )

=  \frac{2}{3}  +  \frac{1}{6}

=  \frac{2 \times 2}{3 \times 2}  +  \frac{1}{6}

=  \frac{4}{6}  +  \frac{1}{6}

=  \frac{5}{6}

Question i:

\frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3}{2}  -  \frac{5}{8} )

=  \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3 \times 4}{2 \times 4}  -  \frac{5}{8} )

= \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{12}{8}  -  \frac{5}{8} )

=  \frac{7}{8}  +  (\frac{1}{4}  \times  \frac{7}{8} )

=  \frac{7}{8}  +  \frac{7}{32}

=  \frac{7  \times 4}{8 \times 4}  +  \frac{7}{32}

=  \frac{28}{32}  +  \frac{7}{32}

=  \frac{35}{32}

Question k:

\frac{3}{4}  - ( \frac{12}{7}  \div  \frac{12}{21} ) +  \frac{4}{5}

=  \frac{3}{4}  - ( \frac{12}{7}  \times  \frac{21}{12} ) +  \frac{4}{5}

=  \frac{3}{4}  -  \frac{3}{1}  +  \frac{4}{5}

= \frac{3 \times 5}{4 \times 5}  -  \frac{3 \times 20}{1 \times 20} +  \frac{4 \times 4}{5 \times 4}

=  \frac{15}{20}   -   \frac{60}{20} +  \frac{16}{20}

=  -  \frac{29}{20}

Question l:

\frac{5}{2}  \times ( \frac{2}{3}  -  \frac{1}{5} ) - ( \frac{2}{5}  \div  \frac{4}{3} )

=  \frac{5}{2}  \times ( \frac{2 \times 5}{3 \times 5}  -  \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5}  \times  \frac{3}{4} )

=  \frac{5}{2}  \times ( \frac{10}{15}  -  \frac{3}{15} ) -  \frac{3}{10}

=  (\frac{5}{2} \times   \frac{7}{15}) -  \frac{3}{10}

=  \frac{7}{6}  -  \frac{3}{10}

=  \frac{7 \times 5}{6 \times 5}  -  \frac{3 \times 3}{10 \times 3}

=  \frac{35}{30}  -  \frac{9}{30}

=  \frac{26}{30}

=  \frac{13}{15}

8 0
3 years ago
The difference of two numbers is equal to 0.6. Their quotient is also 0.6. What are the numbers?
sveticcg [70]
Let one number be x and the other number be y.

The 2 equations are:
x - y = 0.6    --------------- (1)
x/y = 0.6      --------------- (2)

From equation (1):
x - y = 0.6
x = 0.6 + y     --------------- Sub into (2)

\dfrac{0.6 + y}{y} = 0.6

0.6 + y= 0.6y

y - 0.6y = - 0.6

0.4y = - 0.6

y = -0.6 ÷ 0.4

y = -1.5

Sub y = -1.5 into (1):

x - y = 0.6

x - (-1.5) = 0.6

x  + 1.5 = 0.6

x = 0.6 - 1.5

x = - 0.9

Answer: The numbers are -0.9 and -1.5

5 0
3 years ago
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