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3 years ago

MIDPOINT & DISTANCE help

Mathematics

1 answer:

tamaranim1 [39]3 years ago

5 0

Answer:

Step-by-step explanation:

The formula of a midpoint of (x₁, y₁) and (x₂, y₂):

$M\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

We have two points (-3, 7) and (-9, 1).

Substitute:

$x=\dfrac{-3+(-9)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{7+1}{2}=\dfrac{8}{2}=4$

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A softball team played 149 games. The team won 8 more than two times the number of games they lost. How many games did they lose

BlackZzzverrR [31]

The number of game the softball team lose is 47 games.

<h3 /><h3 /><h3>The softball team played 149 games. </h3>

Total games played = 149 games

The team won 8 more than two times the number of games they lost.

Let

the number of games they lost = x

Therefore,

number of game won = 8 + 2x

The number of game they lose can be calculated as follows:

8 + 2x + x = 149

8 + 3x = 149

3x = 149 - 8

3x = 141

x = 141 / 3

x = 47

Therefore, the team lost 47 games.

learn more on algebra here: brainly.com/question/14406047?referrer=searchResults

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3 years ago

The sum of two numbers gives twelve the difference gives two. what are the two numbers

soldier1979 [14.2K]

Answer:

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Step-by-step explanation:

7+5=12 and 7-5=2

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2 years ago

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Given that f(x) = x + 3<br> a) Find f(2)

Nataly_w [17]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

In the above question, it is given that :

$\qquad \sf \boxed{ \sf f(x) = \frac{x + 3}{2} }$

A.) Find f(2) :

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{2 + 3}{2}$

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{5}{2}$

$\qquad \sf \dashrightarrow \: f(2) = 0.5$

B.) Find ${ \sf {f}^{-1}(x) }$ :

$\qquad \sf \dashrightarrow \: let \: y = f (x)$

so, we can write it as :

$\qquad \sf \dashrightarrow \: y = \dfrac{x + 3}{2}$

$\qquad \sf \dashrightarrow \: 2y = x + 3$

$\qquad \sf \dashrightarrow \: x = 2y - 3$

Now, put x = ${ \sf {f}^{-1}(x) }$ , and y = x and we will get our required inverse function ~

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3$

C.) Find ${ \sf {f}^{-1}(12) }$ :

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 36- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 33$

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