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3 years ago

if the measure of <BEC is (2x+3)° and x=30, which expression could represent the measure of <AED?

Mathematics

1 answer:

Maurinko [17]3 years ago

8 0

Answer:

The answer is 3x-27

Step-by-step explanation:

If the angles are vertical from each other it means they are congruent. 2x+30 is 63, you plug in the x, 2(30)+30. You do that to the second one and also get 63, 3(30)-27. Therefore 3x-21 is the answer.

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Domain and Range for the graph

Lena [83]

Answer:

its gos up

Step-by-step explanation:

think it's not hard

3 0

3 years ago

The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard

PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 8.59, \sigma = 0.63$

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{9.08 - 8.59}{0.63}$

$Z = 0.78$

$Z = 0.78$ has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0

3 years ago

Solution please! explain clearly

natali 33 [55]

Answer:

Step-by-step explanation:

For some angle "a", the sine and cosine are related by ...

sin(a) = cos(π/2 -a)

That is,

sin(7π/16) = cos(π/16)

sin(5π/16) = cos(3π/16)

Then your sum becomes ...

sum = sin(π/16)² +sin(3π/16)² +cos(3π/16)² +cos(π/16)²

If we let α = π/16 and β = 3π/16, this can be written as ...

sum = (sin(α)² +cos(α)²) +(sin(β)² +cos(β)²)

sum = 1 + 1

sum = 2

The identity sin(α)² +cos(α)² = 1 is sometimes called the Pythagorean identity.

6 0

3 years ago

Where does the normal line to the paraboloid z = x2 + y2 at the point (1, 1, 2) intersect the paraboloid a second time?

Digiron [165]

Answer:

the intersection point is ( -5/4, -5/4, -9/8)

Step-by-step explanation:

F(x,y,z) = x² +y² -z= 0

Then find differential of each terms then we have

∀f(x)=2x

∀f(y)=2y

∀f(z)=-1

The partial differential which is the director vector is at F(x,y,z)= (1,1,2)

Vf(1,1,2) = (2,2,-1)

But the given point is ( 1.1,2)

Then the parametric equation of normal line will be

x= 1+2t

y= 1+2t

z= 2 -t

The parametric equation can be formed as

(1+2t)² + (1+2t)² - (2-t)= 0

If we expand the expression above we have,

2(1+4t+4t²) - 2+t= 0

0= 8t² + 9t

t= 0 or t= -9/8

Substitute the value of t into the parametric equation above

At t=0

x= 1+2t; x= 1+2(0)=1

y= 1+2t; y= 1+2(0)=1

z=2 -t ; z= 2-(0)= 2

At =0 , we have (1,1,2)

At t= -9/8

x= 1+2t; x= 1+2(-9/8)=-5/4

y= 1+2t; y= 1+2(-9/8)=-5/4

z=2 -t ; z= 2-(-9/8)= -9/8

Therefore, the intersection point is ( -5/4, -5/4, -9/8)

4 0

4 years ago

Solve each system by substitution.

KatRina [158]

Are you looking for x or y, because you put z=...?

3 0

3 years ago

if the measure of <BEC is (2x+3)° and x=30, which expression could represent the measure of <AED?​

if the measure of <BEC is (2x+3)° and x=30, which expression could represent the measure of <AED?