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Mamont248 [21]
3 years ago
8

If your vehicle leaves the pavement for any reason, remember to take your foot off the gas pedal, hold the wheel firmly, and____

___________. Swerve back into the traffic lane Pump the brakes Shift into a low gear Steer in a straight line
Computers and Technology
2 answers:
aleksandr82 [10.1K]3 years ago
8 0
A- and steer in a straight line 
Katen [24]3 years ago
3 0
<h2>Answer:</h2>

<u>The correct option is </u><u>Steer in a straight line</u>

<h2>Explanation:</h2>

When the vehicle gets off the roadway for any reason, the driver must not lose senses and he must focus on the way where he is leading. When he reduces the speed by removing his foot from gas pedal, he must keep an eye on the road and drive in a straight line so that the balance of the car may not disturb. Along with that the driver should shift the gear to the lower gear and then he must get to a side and stop the car.

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3 years ago
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Write a program that will predict the size of a population of organisms. The program // should ask the user for the starting num
nordsb [41]

Answer:

Following are the program in the C++ Programming Language:

#include <iostream>

using namespace std;

int main() {

 float starting, average;

 int num;

 std::cout <<"Enter starting number of the organisms: ";

 while(!(std::cin >> starting)|| starting < 2){

   std::cout<<"starting number must be greater than 2\n";

   std::cout <<"Enter starting number of the organisms: ";

   std::cin.clear();

   std::cin.ignore(123,'\n');

 }

 std::cout <<"Enter the average of daily population is increase %: ";

 while(!(std::cin >> average)|| average < 0){

   std::cout<<"Average must be greater than 0\n Enter average";

   std::cin.clear();

   std::cin.ignore(123,'\n');

 }

   average *= .01;

 std::cout <<"Enter the number of days: ";

 while(!(std::cin >> num)|| num < 1){

   std::cout<<"Number of days no be less than 1\n" <<"Enterthe number of days\n";

   std::cin.clear();

   std::cin.ignore(123,'\n');

 }

 for(int i=0; i<num; i++){

   std::cout<<"population size of day"<<(i+1);

   std::cout<<": "<<starting<<std::endl;

   starting +=(starting*average);

 }

 return 0;

}

<u>Output</u>:

Enter starting number of the organisms: 4

Enter the average of daily population is increase %: 5

Enter the number of days: 4

population size of day1: 4

population size of day2: 4.2

population size of day3: 4.41

population size of day4: 4.6305

Explanation:

Here, we define header file "<iostream>" and namespace "std".

  • Then, we define the main() inside it, we set two float data type variable i.e., "starting", "average" and set an integer data type variable i.e., "num".
  • Then, we print a message and after that, we set the while loop for get input from the user in variable "starting" and pass the condition inside loop we print message than clear cin and ignore 123 then, we again do this to get  input from user in variable "average".
  • Then, we set the for loop and pass the condition inside the loop print the size of the day then print the value of "starting" after that we multiply.
  • Finally, we return 0 and close the main function.
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3 years ago
What would be an ideal scenario for using edge computing solutions?
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An ideal scenario for using edge computing solutions is when there is a  bad network connection  with IoT devices .

<h3>What is Edge computing ?</h3>

Edge computing can be regarded as the process that involves the  analyes as well as the, and storage of data closer to where it is generated .

This is been done to  enable rapid analysis and response in the process that is been used by some companies  to have consolidated operations , hence, An ideal scenario for using edge computing solutions is when there is a  bad network connection  with IoT devices .

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Firlakuza [10]

Answer:

If you are using Python,

```count = 0

for i in range(0, 79):

a = int(input("Input a number: "))

if 100 <= a <= 1000:

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  count += 1

else:

 print("Please input a number between 100 and 1000!")

 i -= 1

print(count)```

Explanation:

count refers to the number of 500s and above,

the for loop is required for the program to loop 80 times,

a is the input collected,

the nested if is to check whether the number is above 500 and the if is used to check if the number is between 100 and 1000 if not, it will output that you need to input a number between 100 and 1000,

the i-=1 is required to make sure that part wasn't counted.

and the last print is to output the number of numbers above 500

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