Answer:
The Correct option is : d. BROADBAND ACCESS enable users to connect to a high speed networks
Explanation:
As the names implies BROADBAND ACCESS can be defined as a technology that enables users to have the access to fast and high speed internet connection when browsing, streaming or downloading reason been that BROADBAND ACCESS is more faster and quicker which inturn enables the user to do a lot more on the internet which is why BROADBAND ACCESS is often refer or known as a high and fast speed Internet access connection.
<span>If a user name can have seven letters (with no distinction between upper and lower case), and if a letter can be repeated, then the maximum number of names is 26x26x26x26x26x26x26, or 8,031,810,176. That is, slightly more than eight billion names are possible.</span>
Bertha should use end roll technique so that she doesn't miss the initial action of a drama.
b. end roll
<u>Explanation:</u>
End roll is a simple method to decide whether the film is pushing ahead or not. When you utilize the film advance to wind the film, you essentially need to check if the handle on the left (that you use to rewind the film) is turning.
In the event that it turns, great, it implies that the film is appropriately locked in. So Bertha should utilize the end move strategy with the goal that she doesn't miss the underlying activity of a dramatization.
Answer:
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Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
The stock market would behave very differently if people had easy access to that data.
