Let L, W and P denote length, width and perimeter.
L = (2/3)W - 5
The perimeter, P, is 2W + 2L, and this, in turn, is
2W + 2((2/3)W - 5), or 2W + (4/3)W - 10, or
(2 + 4/3)W - 10, or (10/3)W - 10
• Expand (2a + b)²:
(2a + b)²
= (2a + b) · (2a + b)
Multiply out the brackets by applying the distributive property of multiplication:
= (2a + b) · 2a + (2a + b) · b
= 2a · 2a + b · 2a + 2a · b + b · b
= 2²a² + 2ab + 2ab + b²
Now, group like terms together, and you get
= 2²a² + 4ab + b²
= 4a² + 4ab + b² <——— expanded form (this is the answer).
I hope this helps. =)
Tags: <em>special product square of a sum algebra</em>
Answer:
21/676
Step-by-step explanation:
The total number of letters of the alphabet will be the total outcome which is 26 alphabets.
If consonant numbers are drawn out, the probability of drawing a consonant will be total consonants/total alphabets
Total consonants in the alphabet is 21.
Probability of drawing consonants = 21/26.
Since all the consonants are replaced before drawing a Z, our total outcome will not change i.e it will still be 26.
Probability of drawing a letter Z will be 1/26.
Therefore, the probability of drawing a consonant,replacing it, and then drawing a Z will be;
21/26×1/26
= 21/676
Answer:
x=-5
Step-by-step explanation:
6x+3=5x-8 subtract 5x from both sides
x+3=-8x subtract 3 from both sides
x=-5
