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igor_vitrenko [27]
3 years ago
10

Absolute Value Inequalities |x−7|+|1−x|>6

Mathematics
2 answers:
skad [1K]3 years ago
5 0

Answer:

x>-1

Step-by-step explanation:

Ugo [173]3 years ago
4 0

Answer:

Step-by-step explanation:

|x-7|+|1-x|>6\\\\\mathrm{For\:each\:absolute\:find\:positive\:and\:negative\:intervals}\\\\\mathrm{For\:}x\le \:1:\quad x

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Step-by-step explanation

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Complete the solution of the equation find the value of y when x equals 2. -8x - 5y = -1
tatuchka [14]

Answer: y = -3

<u>Step-by-step explanation:</u>

-8x - 5y = -1

<u>+8x        </u>  <u>+8x </u>

       -5y = 8x  - 1

       <u> ÷-5 </u> <u> ÷-5</u>  <u>÷-5</u>

           y = -\frac{8}{5}x + \frac{1}{5}

       y(2) = -\frac{8}{5}(2) + \frac{1}{5}

               = -\frac{16}{5} + \frac{1}{5}

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3 years ago
PLZ help me fast 2 mins left
jek_recluse [69]

Answer:

\sqrt{-5}=i\sqrt{5}

\sqrt{-25}=5i

Step-by-step explanation:

i is an imaginary unit, this means

i^2=-1

Rewrite -5 as 5\cdot (-1)=5\cdot i^2,

then

\sqrt{-5}=\sqrt{5i^2}=\sqrt{5}\cdot \sqrt{i^2}=\sqrt{5}\cdot i=i\sqrt{5}

Rewrite -25 as -25=25\cdot (-1)=25\cdot i^2,

then

\sqrt{-25}=\sqrt{25\cdot i^2}=\sqrt{25}\cdot \sqrt{i^2}=5\cdot i=5i

6 0
3 years ago
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