I need help. I will give you 10 points.
1 answer:
You might be interested in
Answer:
a) 31.38%
b) 28.44%
c) 33.33%
d) 73.46%
e) 53.89%
Step-by-step explanation:
<h3>(See picture attached for sub-totals) </h3>a) What is the probability of selecting a student whose favorite sport is skiing?
P = 171/545 = 0.3138 = 31.38%
b) What is the probability of selecting a 6th grade student?
P = 155/545 = 0.2844 = 28.44%
c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?
P = 70/210 = 0.3333 = 33.33%
d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?
P = 155/211 = 0.7346 = 73.46%
e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?
P = 180/(171+163) = 180/334 = 0.5389 = 53.89%
Answer:
Probability both are nervous around strangers = 0.0049
Probability at least one is nervous around strangers = 0.1302
Step-by-step explanation:
Let probability a person selected in the population is nervous around strangers = P
P = 7%
P =
P = 0.07
Let probability a person selected in the population is not nervous around strangers = P'
P' = 1 - P
P' = 1 - 0.07
P' = 0.93
(i) probability of the first person selected is nervous around strangers = P
probability of the second person selected is nervous around strangers = P
Probability both are nervous around strangers = (P × P)
= 0.07 × 0.07
= 0.0049
(ii) Probability at least one is nervous around strangers = ( probability the first person is nervous around strangers AND the second person is not nervous around strangers ) OR ( probability the second person is nervous around strangers AND the first person is not nervous around strangers)
This implies,
Probability at least one is nervous around strangers = (P × P') or (P × P')
= (0.07 × 0.93) + (0.07 × 0.93)
= 0.0651 + 0.0651
= 0.1302