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Andreyy89
3 years ago
8

I need help. I will give you 10 points.​

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

rectangle perimeter= w+w+2(2w-6)

triangle perimeter= 3(w+8)

perimeter of rectangle= 6w-12

triangle perimeter= 3w+24

Step-by-step explanation:

You might be interested in
2. The distance between two towns is 7 km. On a map, the distance between the towns is 28 cm. Find, as a ratio, the scale of the
liberstina [14]

scale of the drawing = original dimensions / dimensions of the scale drawing

7/28

Ans 1:4

Answered by GauthMath please heart it and comment thanks if you like

4 0
4 years ago
Tony throws the dice once.He also throws a coin to get heads or tails.Two of the outcomes are 1H 2H
aleksley [76]

Answer:

  • <u>1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, and 6T.</u>

Explanation:

The quetion is:

  • <em>list all the outcomes in the same format </em>
<h2 /><h2>Solution</h2>

Understand the format:

  • first character is the number that appears on the top face of the dice: it can be 1, 2, 3, 4, 5, or 6.

  • second charater is one of two letters that represent the flip of the coin: H for heads or T for tails.

Then, the list of the combinations that represent all the possible outcomes is:

  • 1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, and 6T.

They are 12 possible outcomes: 6 × 2 = 12: 6 from the 6 possible outmoes of the dice, and 2 for the two possible outcomes of the coin.

4 0
4 years ago
Si la poblacion de india es de 1,189,173,000 de habitantes, aproximadamente, y la tercera parte son menores de 15 años cuantos n
Zina [86]

Answer:

There are 396,391,000 people smaller than 15 in India.

396,391,000 niños de esa edad hay en India

Step-by-step explanation:

We have that:

India has 1,189,173,000 habitants.

A third of this is smaller than 15.

How many people smaller than 15 are there in India?

(1/3)*1,189,173,000 = 396,391,000

There are 396,391,000 people smaller than 15 in India.

396,391,000 niños de esa edad hay en India

6 0
3 years ago
if the roots of the equations(given in the picture as question no. 3) are simultaneously real then prove that b2=ac
makkiz [27]
Hi,
1) ax²+2bx+c=0 have real roots then (2b)²-4ac>=0 ==> 4b²>=4ac ==> b²>=ac
2)  bx²-2√(ac)x+b=0 have real roots then 
(-2√(ac))²-4b²>=0==> 4ac>=4b²==> ac>=b²
So b²>=ac>=b²==> b²=ac

8 0
4 years ago
At the beginning of the school year, Jamie had $500 in her savings account. She wants to have at least $200 left in the account
UNO [17]

Her error was that she misplaced the numbers

-30x ≥ -300

its supose

to be -30x ≥ 200

7 0
3 years ago
Read 2 more answers
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