Suppose you roll a die 5 times. What is the probability of getting at least one odd number ?

Mathematics

1 answer:

Simora [160]2 years ago

3 0

Answer: 1/2 or 50%

Step-by-step explanation:

A dice has 6 numbers; 1,2,3,4,5,6

3 of which are odd numbers

which means:

p(event)= number of favorable outcomes/ number of possible outcomes

p(odd)=3/6

3/6=1/2 or 50%

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saveliy_v [14]

Answer:

Yes

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .