All categories

2 years ago

Suppose you roll a die 5 times. What is the probability of getting at least one odd number ?

Mathematics

1 answer:

Simora [160]2 years ago

3 0

Answer: 1/2 or 50%

Step-by-step explanation:

A dice has 6 numbers; 1,2,3,4,5,6

3 of which are odd numbers

which means:

p(event)= number of favorable outcomes/ number of possible outcomes

p(odd)=3/6

3/6=1/2 or 50%

You might be interested in

Find the area of the polygon. 32 m 20 m 16 m 40 m he area of the polygon is square meters.

jenyasd209 [6]

Answer:

Step-by-step explanation:

4 0

3 years ago

HELPP ASAP!!!!! Rectangle RSTU and the image R’S’T’U’ are graphed on the coordinate grid below.

mylen [45]

270° clockwise rotation & 90° counterclockwise rotation

6 0

3 years ago

Read 2 more answers

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

Please HELP!!!!!

Stels [109]

Can you explain it more clear because my english is not very good, I want to easy to help you

3 0

3 years ago

Lois and Clark own a company that sells wagons. The amount they pay each of their sales employees (in dollars) is given by the e

ira [324]

You can replace the h and w with 6 and 3 in the expression. Then the expression is 12*6+30*3=162 dollars. So the amount paid to this employee is 162 dollars.

4 0

3 years ago

Suppose you roll a die 5 times. What is the probability of getting at least one odd number ​?

Suppose you roll a die 5 times. What is the probability of getting at least one odd number ?