For table # 1:
x= 1 * 3.5 = 3.5
x = 2*3.5 = 7
x = 3*3.5 = 10.5
x = 4* 3.5 = 14
For table #2
x=1 * 3 = 3
x =2 * 3 = 6
x = 3*3 = 9
x = 4* 3 = 12
Hence, the data sets show multiplicative relationships:
For data set 1 is 3.5 times x, and in data set 2 y is 3 times x.
This is a difference of perfect squares which is of the form:
(a^2-b^2)
And which always factors to:
(a-b)(a+b)
In this case:
(5x-8)(5x+8)
