Answer
m<3 = 49°
Step-by-step explanation:
It is given that,
M∥n, m∠1 = 50°, m∠2 = 48°, and line s bisects ∠ABC
m<DEF = m<1 + m<2 = 50° + 48° = 98°
Corresponding angle of <DEF is equal to <ABC = 98°
To find m<3
< 4 = <5 = 98/2 = 49° (Since line s bisects ∠ABC)
Therefore,
m<3 = 49° (< 4 and <3 are vertically opposite angles)
Answer: 14%
Step-by-step explanation: 7/50 = 14/100 = .14 = 14%
F is increasing if f '(x) = 4x^3<span> - 64x >0, so it is the same of x(x^2 -16)>0, implies x>0 or (x-4)(x+4)>0, so x> + or -4
the answer is </span><span>(-4 , 0) ∪ (4 , infinity)
</span>f is decreasing if f '(x) = 4x^3 - 64x <0, so it is the same of x(x^2 -16)<0, implies x<0 or (x-4)(x+4)<0, so x< + or -4
the answer is (- infinity, -4) ∪ (0 , 4)
<span>the local minimum and maximum
</span>f '(x) =0, impolies x=+ or -4, or x=0
or f'(o)=0, and f'(- 4)=f'(4)= 0,
M(-4, 0) or M(4, 0) or M(0,0)
<span>inflection points can be found by solving f '' (x)=12x^2 - 64 =0
</span>x=+ or - 4sqrt(3) / 3
so the inflection point is and M(- 4sqrt(3) / 3, f'' ( -4sqrt(3)) (smaller x value), and M(4sqrt(3) / 3, f'' (4sqrt(3)) (larger x value)
f is concave up if f ''>0
it means 12x^2 - 64>0, so the interval is (- infinity, -4sqrt(3) U (4sqrt(3), infinity)
f is concave down if f ''<0
it means 12x^2 - 64<0 so the interval is (-4sqrt(3)) U (4sqrt(3))
20/11=20 divided by 11
1.8181818181818...
