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jolli1 [7]
3 years ago
8

How does 1/12 - 5/6 = 9/12 um tring to learn how to add this like ?

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

1/12 - 5/6 = -9/12

We need to get a common denominator of 12

1/12 - 5/6*2/2 = -9 /12

1/12 - 10/12 = -9/12

Since the denominators are the same, we can subtract the numerators

1-10 = -9

-9/12 = - 9/12

We can simplify -9/12 by dividing the top and bottom by 3

-9/3 = -3

12 /3 = 4

-9/12 = -3/4

harina [27]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

1/12 - 5/6 = -9/12

1st, we need to identify the Least Common Multiplier of 12 and 6

in this case, the LCM is 12

for 5/6 = (5*2) / (6*2) = 10/12

2nd, adjust the fractions based on the LCM

= 1 / 12  -  10 / 12

= 1 - 10 / 12

= -9 / 12 ---- simplify   -3 / 4

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Answer:

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5 0
3 years ago
What is the sum of a 7-term geometric series if the first term is -6, the last term is -24,576, and the common ratio is 4?
Zanzabum
<h3><u>Answer:</u></h3>

Hence, the sum of a 7-term geometric series is:

-32766.

<h3><u>Step-by-step explanation:</u></h3>

We have to find the sum of a 7-term geometric series (i.e. n=7) if the first term(a) is -6, the last term is -24,576, and the common ratio(r) is 4.

We know that the sum of the 7-term geometric series is given as:

S_n=a\times (\dfrac{r^n-1}{r-1})

On putting the value of a,n and r in the given formula we have:

S_7=(-6)\times (\dfrac{4^7-1}{4-1})\\\\\\S_7=-32766

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3 0
3 years ago
Read 2 more answers
A taxi service charges a 10$ initial fee and an additional $1.25 per minute.
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3 years ago
A line is tangent to the circle x^2+y^2=41, at the point (-4,-5)
VashaNatasha [74]
If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
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(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)

Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0). 

The formula for slope is <u>Y1-Y2</u>
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We can break this down with our two points (center and tangent)
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(X1,Y1) and (X2,Y2)

therefore, we will put the equation as such
<u>0-(-5)= 5</u>  = <em> </em><u><em>5</em></u>
0-(-4)= 4     <em> 4</em>

<em>this is our slope from the center to the point of tangency.</em>

We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to. 

Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
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Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.

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now we plug things in
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5

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Now we just need to rewrite our equation with all our components.
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</u>5
1 <u>4</u> = y-intercept<u>
</u>   5

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Hope that helped
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masha68 [24]

Answer:18

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7 0
3 years ago
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