Answer:
Option d :18 bags of chips and 6 jars of salsa
Step-by-step explanation:
Given : The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag and salsa, which costs $4 per jar. The chips & salsa budget you are given totals $60.
Inequality : 
Solution :
x represents chips
y represents salsa
Option a: 10 bags of chips and 2 jars of salsa
so, x = 10 and y =2
Putting values in inequality
Hence it is correct.
Option b : 20 bags of chips and 2 jars of salsa
so, x = 20 and y =2
Putting values in inequality
Hence it is correct.
Option c : 14 bags of chips and 5 jars of salsa
so, x = 14 and y =5
Putting values in inequality
Hence it is correct.
Option d :18 bags of chips and 6 jars of salsa
so, x = 18 and y =6
Putting values in inequality
Hence it is not correct since it violates the inequality
Answer:
A
Step-by-step explanation:
- 1/5 of 5x is -1 or just -x and -1/5 of 20 is -4. Then the other one is-1/4 of 4 is -x and -1/4 of -28 is 7. Now combine like terms so -x + -x is -2x and 7+ -4 or 7-4 is 3
Step-by-step explanation:
The formula is Distance=√(x2-x1)²+(y2 -y1)²
x1 is 5, x2 is 1, y1 is 9, y2 is 6
D = √( 1-5)² +(6-9)²
D = √(-4)²+(-3)²
D = √16+9
D = √25
D = 5 units
1
Simplify \frac{1}{2}\imath n(x+3)21ın(x+3) to \frac{\imath n(x+3)}{2}2ın(x+3)
\frac{\imath n(x+3)}{2}-\imath nx=02ın(x+3)−ınx=0
2
Add \imath nxınx to both sides
\frac{\imath n(x+3)}{2}=\imath nx2ın(x+3)=ınx
3
Multiply both sides by 22
\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2
4
Regroup terms
\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı
5
Cancel \imathı on both sides
n(x+3)=nx\times 2n(x+3)=nx×2
6
Divide both sides by nn
x+3=\frac{nx\times 2}{n}x+3=nnx×2
7
Subtract 33 from both sides
x=\frac{nx\times 2}{n}-3x=nnx×2−3
