Answer:
if i can be brainliest that would be great
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
Answer:
Value of ![[(\frac{2}{3}) ^0]^{-3}](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B2%7D%7B3%7D%29%20%5E0%5D%5E%7B-3%7D)
is, 1
Step-by-step explanation:
To find the value of ![[(\frac{2}{3})^0]^{-3}](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B2%7D%7B3%7D%29%5E0%5D%5E%7B-3%7D)
Using exponents power rule:
then;
Simplify:
By Zero exponent rule: Anything raised to the power 0 is 1. i.e,
then;
= 1
Therefore, the value of is, 1
Answer:
40 ft
Step-by-step explanation:
The fiagram shows the right triangle (one angle is right angle).
By the Pythagorean theorem,
From the diagram,
then
Answer: B) 3
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f(0) = 3 is the given initial term
f(n+1) = -f(n)+5 is the recursive rule
Plug in n = 0 to find the next term
f(n+1) = -f(n)+5
f(0+1) = -f(0)+5 ... replace every n with 0
f(1) = -3+5 ... replace f(0) with 3
f(1) = 2
The second term is f(1) = 2
Then plug in n = 1 to find the next term after that
f(n+1) = -f(n)+5
f(1+1) = -f(1)+5 ... replace n with 1
f(2) = -2+5 ...... replace f(1) with 2
f(2) = 3
we stop here because we found the value for f(2)
Answer:
a and e
Step-by-step explanation:
