It’s quite easy if I got you right...
80$ : 40h = 2$/h
4x³=756
x³=189
x=3 ³√7 should be acceptable
☺☺☺☺
3x-y=2....(i)
2x-y=3.....(ii)
now adding the eqn I and ii ,
3x-y=2
2x-y=3
+ + +
5x=5
x=1
Now substituting the value of x in eqn I
3×1-y=2
3-y=2
-y=-1
y=1
The answer to the questions
