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3 years ago

15

Here are two five-pointed stars. A student said, “Both figures A and B are polygons. They are both composed of line segments and

are two-dimensional. Neither have curves.” Do you agree with the statement? Explain your reasoning.

2 answers:

Natali5045456 [20]3 years ago

6 0

Answer:

A because I said so poopy head

Alex3 years ago

4 0

Answer:A

Step-by-step explanation:

Bcnitsreksbeux

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WILL GIVE BRAINLEST ANSWER IF ANSWERED IN THE NEXT 24 HRS Express the complex number in trigonometric form. -5i

trasher [3.6K]

Answer:

$z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)$

Step-by-step explanation:

If a complex number is z=a+ib, then the trigonometric form of complex number is

$z=r(\cos \theta +i\sin \theta)$

where, $r=\sqrt{a^2+b^2}$ and $\tan \theta=\dfrac{b}{a}$ , $\theta$ is called the argument of z, $0\leq \theta\leq 2\pi$ .

The given complex number is -5i.

It can be rewritten as

$z=0-5i$

Here, a=0 and b=-5. $\theta$ lies in 4th quadrant.

$r=\sqrt{0^2+(-5)^2}=5$

$\tan \theta=\dfrac{-5}{0}$

$\tan \theta=\infty$

$\theta=2\pi -\dfrac{\pi}{2}$ $[\because \text{In 4th quadrant }\theta=2\pi-\theta]$

$\theta=\dfrac{3\pi}{2}$

So, the trigonometric form is

$z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)$

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3 years ago

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PLEASE HELP FOR BRAINLEIST ANSWER AND 30 POINTS THANKYOU IN ADVANCED YOU ARE TOO KIND :)

stealth61 [152]

It is Figures A,B, and C. Answer D is not a polygon.

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Type SSS, SAS, ASA, SAA, or HL to

Tems11 [23]

9514 1404 393

Answer:

ASA

Step-by-step explanation:

The shared angle, the marked angle, and the marked sides between those angles are congruent. That is, you have congruent Angle, Side, Angle, so the ASA postulate applies.

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3 years ago

If h (x) = {(-2,3), (0,4), (1,6), (2, 9)}<br><br> then what set of values represent h-1 (x) ?

vfiekz [6]

Answer:

$h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}$

Step-by-step explanation:

Given: $h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}$

To find: $h^{-1}(x)$

Solution:

A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.

Inverse of a function exist if it is both one to one and onto.

$h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}$

$h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}$

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The expanded form of 6,398 is

masya89 [10]

Answer:

The expanded form of 6,398 is 6000 + 300 + 90 + 8

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