56 less than x cubed

Mathematics

2 answers:

dexar [7]4 years ago

5 0

56 is less than x? Just multiply

Anestetic [448]4 years ago

4 0

Find the square root of 56 will be equal to x

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When simplifying the fraction 2x/4, madison wrote 2x/4 = 2x. EXPLAIN WHY her answer is wrong and write the correct answer.

antiseptic1488 [7]

Answer:

x/2

Step-by-step explanation:

Madison didn't cancel the common factor of 2 and that 4 that is why she is wrong.

Hope this helps pls brainliest have a nice day :>

5 0

2 years ago

Solve 8[7 - (6x -6)] + 6x =0.

Rus_ich [418]

Solve for x:8 (13 - 6 x) + 6 x = 0
8 (13 - 6 x) = 104 - 48 x:
6 x + 104 - 48 x = 0
6 x - 48 x = -42 x:
-42 x + 104 = 0
Subtract 104 from both sides:
(104 - 104) - 42 x = -104
104 - 104 = 0:
-42 x = -104
Divide both sides of -42 x = -104 by -42:
(-42 x)/(-42) = -104/(-42)
(-42)/(-42) = 1:
x = -104/(-42)
The gcd of 104 and -42 is 2, so -104/(-42) = -(2×52)/(2 (-21)) = 2/2×(-52)/(-21) = (-52)/(-21):
x = (-52)/-21
Multiply numerator and denominator of (-52)/(-21) by -1:
Answer: x = 52/21

8 0

4 years ago

Find the standard form of the equation of the parabola with a focus at (-2, 0) and a directrix at x = 2.

krok68 [10]

Answer:

$y^2=\frac{1}{8}x$

Step-by-step explanation:

The focus lies on the x axis and the directrix is a vertical line through x = 2. The parabola, by nature, wraps around the focus, or "forms" its shape about the focus. That means that this is a "sideways" parabola, a "y^2" type instead of an "x^2" type. The standard form for this type is

$(x-h)=4p(y-k)^2$

where h and k are the coordinates of the vertex and p is the distance from the vertex to either the focus or the directrix (that distance is the same; we only need to find one). That means that the vertex has to be equidistant from the focus and the directrix. If the focus is at x = -2 y = 0 and the directrix is at x = 2, midway between them is the origin (0, 0). So h = 0 and k = 0. p is the number of units from the vertex to the focus (or directrix). That means that p=2. We fill in our equation now with the info we have:

$(x-0)=4(2)(y-0)^2$