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4 years ago

120 divided (2-4) exponent 2 plus 2*3

Mathematics

1 answer:

Murljashka [212]4 years ago

7 0

120/(2-4)^2+2*3=36

You have to use bedmas or the order of operations

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What is 782,943 rounded to the nearest ten thousand

Effectus [21]

The answer is 780,000

3 0

3 years ago

Read 2 more answers

f a rectangle has a perimeter of 70, a length of x and a width of x - 9, find the value of the length of the rectangle.

trasher [3.6K]

$( x + (x - 9)) \times 2 = 70 \\( 2x - 9) \times2= 70 \\ 4x - 18 = 70 \\ 4x = 70 + 18 = 88$
$x = \frac{88}{4} = 22$
the length is 22

and the width is
22-9=17

good luck

3 0

3 years ago

Y=3x−4<br> y=−12x+3<br> solution <br> solve by graphing

Anna11 [10]

Answer:

(7/15,−13/5)

Equation Form:

x=7/15,y=−13/5

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

7 0

3 years ago

What is the answer need ASAP

ArbitrLikvidat [17]

ANSWER

C. 58°

EXPLANATION

The sum of the interior angles of a triangle is 180°.

We sum all the three angles to obtain,

$8x+(14x+2)+(10x+50)=180$ .

We group like terms to get,

$8x+14x+10x+2+50=180$ .

Simplify,

$32x+52=180$ .

Combine like terms to get,

$32x=180-52$ .

Simplify,

$32x=128$ .

Divide both sides by 32 to get,

$x=4$ .

We substitute the value of x into the expression for

$m\:$ .

This implies that,

$m\:$ .

The correct answer is C

8 0

3 years ago

The graphs of the equations $y=3x-20$ and $y=-2x+10$ intersect at the point $(6,-2)$. Without solving, find the solution of the

Maru [420]

Answer:

The solution is

$\boxed{x=6,y=-2}$

Step-by-step explanation:

The given equations are

$y=3x-20$

and

$y=-2x+10$

The graph of the two equations intersects at $(6,-2)$ as show in the graph in the attachment.

The point of intersection of the two graphs is the solution to system of equations.

Hence the solution is

$x=6,y=-2$

4 0

3 years ago