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laiz [17]
2 years ago
8

Please help i need the answer asap!

Mathematics
1 answer:
serg [7]2 years ago
6 0
92
Because similar triangles has congruent corresponding angle measures
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I would say it's not reasonable. the answer would be the first one

Step-by-step explanation:

6 0
2 years ago
Pls help me in this i really need help :( :)
Andrews [41]

Hello and Good Morning/Afternoon:

<u>Let's take this problem step-by-step:</u>

<u>First off, let's write the line in point-slope form:</u>

  \rm \hookrightarrow (y-y_0)=m(x-x_0)

  • (x₀, y₀) any random point on the line
  • 'm' is the value of the slope

<u>Let's calculate the slope:</u>

 \rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}

  • (x₁, y₁): any random point on the line                                     ⇒   (-2, -6)
  • (x₂,y₂): any random point on the line that is not (x₁, y₁)         ⇒   (2, -3)

                 \rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}

<u>Now that we found the slope, let's put it into the point-slope form</u>

  ⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

     (y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)

<u>The equation, however, could also be put into 'slope-intercept form'</u>

     ⇒ gotten by isolating the 'y' variable to the left

          y = \frac{3}{4}x-\frac{9}{2}  

<u>Answer:</u>y = \frac{3}{4}x-\frac{9}{2} or y+3=\frac{3}{4} (x-2)

   *<em>Either equations work, put the one that you are the most familiar with</em>

Hope that helps!

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