The probability that a 2 or 3 is rolled at least once is 0.14.
<h3>
Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
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Answer:
C(-1) = -5.
Step-by-step explanation:
C(x) = -4x² + 4x + 3
Plug in -1 for x to solve for C(-1):
C(-1) = -4(-1)² + 4(-1) + 3
Simplify:
C(-1) = -4 + (-4) + 3
C(-1) = -5
Your answer should be xy.
Answer:
127.80
Step-by-step explanation:
14 ÷ 51.10 = 3.65
3.65 × 35 = 127.75
127.75 = 127.80 (rounded off)
Answer:
Linear
Step-by-step explanation:
We are adding by 5 everytime so it is linear!
9 + 5 = 14
14 + 5 = 19
19 + 5 = 24
