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svetoff [14.1K]
3 years ago
9

List all possible permutations

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

1. 1, 2, 3 has 3! = 6 possible permutations:

1 2 3 // 1 3 2 // 2 1 3 // 2 3 1 // 3 1 2 // 3 2 1

2. T, V, W taken 2 at a time has \dfrac{3!}{(3-2)!}=6 possible permutations:

T V // T W // V T // V W // W T // W V

3. I'll replace these symbols with f, s, h, and t (face, sun, heart, triangle). This sequence has \dfrac{4!}{(4-2)!}=12 possible permutations:

f s // f h // f t // s f // s h // s t // h f // h s // h t // t f // t s // t h

4. This has 4! = 24 possible permutations.

A B C D // A B D C // A C B D // A C D B // A D B C // A D C B //

B A C D // B A D C // B C A D // B C D A // B D A C // B D C A //

C A B D // C A D B // C B A D // C B D A // C D A B // C D B A //

D A B C // D A C B // D B A C // D B C A // D C A B // D C B A

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