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alex41 [277]
3 years ago
9

Explain what happens when you round 4.999 to the nearest tenth

Mathematics
2 answers:
Allushta [10]3 years ago
4 0
Tenth place is the first place after the decimal which is 4.999
^
The answer is 4.9
Vera_Pavlovna [14]3 years ago
4 0
4.999 rounded to the nearest tenth which is the first 9 (4.999) would be 5.000 because (4.999) is bigger than 5. you would round up to a solid 5
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Lorico [155]

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What is the slope of the line whose equation is<br> 2y = 5x + 4?<br> 1) 5 2) 2 3) 5/2 4) 2/5
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Answer:

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Step-by-step explanation:

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2 years ago
Two different suppliers, A and B, provide a manufacturer with the same part. All supplies of this part are kept in a large bin.
koban [17]

Answer:

The probability of selecting a non-defective part provided by supplier A is 0.807.

Step-by-step explanation:

Let <em>A</em> = a part is supplied by supplier A, <em>B</em> = a part is supplied by supplier B and <em>D</em> = a part is defective.

<u>Given</u>:

P (D|A) = 0.05, P(D|B) = 0.09

A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.

Then the probability of event <em>A</em> and <em>B</em> is:

P(A)=\frac{n(A)}{n(A)+N(B)}= \frac{4}{4+1}=0.80\\P(B)\frac{n(B)}{n(A)+N(B)}= \frac{1}{4+1}=0.20

Compute the probability of selecting a defective product:

P(D)=P(D|A)P(A)+P(D|B)P(B)\\=(0.05\times0.80)+(0.09\times0.20)\\=0.058

The probability of selecting a non-defective part provided by supplier A is:

P(A|D')=\frac{P(D'|A)P(A)}{P(D')} = \frac{(1-P(D|A))P(A)}{1-P(D)}\\=\frac{(1-0.05)\times0.80}{(1-0.058)}\\ =0.80679\\\approx0.807

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.

5 0
3 years ago
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irina1246 [14]

Answer:

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