S2.256 T2.22 U2.099 V2.71

Mathematics

1 answer:

77julia77 [94]2 years ago

6 0

Answer:

D) V, S, T, U

Step-by-step explanation:

Note that the question is asking for the order from greatest to least. In the case of decimals, I find it easier to compare by placing them in a line going down and filling in zeros where needed to make them the same place values:

2.256 - S

2.220 - T

2.099 - U

2.710 - V

Since they all have the same first digit, I will look at the next digit following the decimal. '7' is the greatest, then '25', then '22' then '09':

D) V, S, T, U

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4 2/5 divided by 6 equal what

sergejj [24]

Answer:

$\frac{22}{30}$

Step-by-step explanation:

$4\frac{2}{5}$ ÷ 6

$\frac{22}{5}$ ÷ 6

$\frac{22}{30}$

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Solve 5c 4 = -26 a. 6 b. -6 c. -4.4 d. 3

lakkis [162]

Simplifying 5C + -4 + -2C + 1 = 8C + 2 Reorder the terms: -4 + 1 + 5C + -2C = 8C + 2 Combine like terms: -4 + 1 = -3 -3 + 5C + -2C = 8C + 2 Combine like terms: 5C + -2C = 3C -3 + 3C = 8C + 2 Reorder the terms: -3 + 3C = 2 + 8C Solving -3 + 3C = 2 + 8C Solving for variable 'C'. Move all terms containing C to the left, all other terms to the right. Add '-8C' to each side of the equation. -3 + 3C + -8C = 2 + 8C + -8C Combine like terms: 3C + -8C = -5C-3 + -5C = 2 + 8C + -8C Combine like terms: 8C + -8C = 0 -3 + -5C = 2 + 0 -3 + -5C = 2 Add '3' to each side of the equation. -3 + 3 + -5C = 2 + 3 Combine like terms: -3 + 3 = 0 0 + -5C = 2 + 3 -5C = 2 + 3 Combine like terms: 2 + 3 = 5 -5C = 5 Divide each side by '-5'. C = -1 Simplifying C = -1

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2 years ago

What is partial derivative of z=(2x+3y)^10 with respect to x,y?

maw [93]

Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.

$\dfrac\partial{\partial x}(2x+3y)^{10}=10(2x+3y)^9\times2=20(2x+3y)^9$

$\dfrac\partial{\partial y}(2x+3y)^{10}=10(2x+3y)^9\times3=30(2x+3y)^9$

Or, if you actually did want the second order derivative,

$\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8$

and in case you meant the other way around, no need to compute that, as $z_{xy}=z_{yx}$ by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because $z$ is a polynomial).