Answer:
<h2>approximately 4%</h2>
Explanation:
Given, frequency of recessive allele (p )= 0.02
so, the frequency of dominant allele is (q )= 1-p
so q = 1-p
p = 0.02
q = 1- 0.02
q = 0.98
Once we know p and q, which factor of the Hardy-Weinberg equation. we can calculate percentage of individuals who are carriers of lethal recessive allele.
so
Result : percentage of individuals who are carriers of the lethal recessive allele is 4%.