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muminat
3 years ago
6

What’s 5 4/9 as an improper fraction

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer: 49/9

Step-by-step explanation:

9x5=45

45+4=49

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emmasim [6.3K]
X=-33 y= 10

Leave first row the same multiply 2nd row by -1
-2x+8y=14
2x+2y=26
10y= 40
Y=4
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5) On the angle above, draw /ABD so that /ABD and /ABC are complementary angels. Label the new angel.
Goryan [66]
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What is the area of △FGH to the nearest tenth of a square meter? The image is of a triangle GHF with base GH length 2m, FG is 2.
Gnesinka [82]
First, we are going to use the law of cosines to find the length of the line segment FH:
FH= \sqrt{2.5^{2}+2^{2}-(2)(2.5)Cos(121)}
FH= \sqrt{2.5^{2}+2^{2}-5Cos(121)}
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Next, we are going to use the semi-perimeter formula: s= \frac{GH+FG+FH}{2}
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s= \frac{7.7}{2}
s=3.9

Now that we have the semi-perimeter of our triangle, we can find its area using Heron's formula:
A= \sqrt{s(s-GH)(s-FG)(s-FH)}
A= \sqrt{3.9(3.9-2)(3.9-2.5)(3.9-3.2)}
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3 0
3 years ago
Suppose that the number of customers that enter a bank in an hour is a Poisson random variable, and suppose that P(X = 0) = 0.09
Ksju [112]

Answer:

E(X) = V(X) = 2.41

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

In the Poisson distribution, the mean is the same as the variance.

P(X = 0) = 0.09

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-\mu}*\mu^{0}}{(0)!} = e^{-\mu}

So

e^{-\mu} = 0.09

We apply ln to both sides, which is the inverse operation of the exponential.

So

\ln{e^{-\mu}} = \ln{0.09}

-\mu = -2.41

Multiplying by -1

\mu = 2.41

So

E(X) = V(X) = 2.41

8 0
3 years ago
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