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nalin [4]
3 years ago
10

Kurt says factors and multiples are

Mathematics
1 answer:
maxonik [38]3 years ago
4 0

<u>Step-by-step Explanation:</u>

<em>Before heading towards the solution, you need to make sure how multiple and factors are related to each other.</em>

<em>The multiple of a number could be obtained by multiply it with another number. </em>

For example, the first five multiples of 12 are 12, 24, 36, 48 and 60

  • 1 X 12 = 12
  • 2 X 12 = 24
  • 3 X 12 = 36
  • 4 X 12 = 48
  • 5 X 12 = 60

<em>Factors are the numbers that are multiplied to get a given number.</em>

For example,

  • 1 X 12 = 12
  • 2 X 12 = 24
  • 3 X 12 = 36

The factors of 12 are 1, 2, 3, 4, 6 and 12.

As division and multiplication can be used to find factors and multiples.

For example a whole number is a multiple of its factors.

Let w = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20} be the set of even wholes numbers from 2 to 20.

As 2 is a factor of 20 because 20 ÷ 2 = 4

20 is a multiple of 2 because 2 X 10 = 20

So, in the same way, the equation 8 X 5 = 40 can be used to determine how factors and multiples are related.

Let the equation be

                                    8 X 5 = 40

8 is a factor of 40 because 8 X 5 = 40

40 is a multiple of 8 because 40 ÷ 5 = 8

<em>So, this is how factors and multiples are related to each other.</em>

<em />

<em>Keywords: factors, multiples, division, multiplication</em>

<em> Learn more about factors and multiples from brainly.com/question/596356</em>

<em> #learnwithBrainly</em>

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Answer:

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Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
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5 0
3 years ago
Solve 7r+ 2 = 5(r – 4) ​
AveGali [126]

Multiply the bracket by 5

I used PEMDAS

P= parenthesis

E= exponents

M=multiplication

D= division

A= addition

S= subtraction

7r+2= 5(r-4)

7r+2= 5r-20

Move 5r to the left hand side . Positive 5r changes to negative 5r

7r-5r+2= 5r-5r-20

2r+2=- 20

2r+2-2= -20-2

Move positive 2 to the right hand side. Changes to negative -2

2r+2-2= -20-2

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6 0
3 years ago
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You and your sister each want to sit in the front seat of your mom’s car. For each of the following, decide if the
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4 years ago
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Neko [114]

Given:

AD is an angle bisector in triangle ABC. m\angle CAB=44^\circ, m\angle ACB=72^\circ, m\angle ABC=64^\circ.

To find:

The value of m\angle ADC.

Solution:

AD is an angle bisector in triangle ABC.

m\angle CAD=m\angle BAD=\dfrac{m\angle CAB}{2}

m\angle CAD=m\angle BAD=\dfrac{44^\circ}{2}

m\angle CAD=m\angle BAD=22^\circ

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.

Using angle sum property in triangle CAD, we get

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22^\circ+m\angle ADC+72^\circ=180^\circ

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m\angle ADC=180^\circ-94^\circ

m\angle ADC=86^\circ

Therefore, the angle of angle ADC is 86^\circ.

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