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MrMuchimi
3 years ago
12

Simplify. (Polynomials)

Mathematics
2 answers:
Mrac [35]3 years ago
8 0
1.(2cd^{3})(-2c)(3cd)
   -12c^{3}d^{4}

2.(2x^{2})(3x^{6}) - (4x^{4})(2x^{4})
   6x^{8} - 8x^{8}
   -2x^{8}

3.(6x^{2})(3x^{6}) + (4x^{4})(2x^{4})
   18x^{8} + 8x^{8}
   26x^{8}

4.(2ab^{2})^{2}(-3a^{2}b^{2})
   ((2ab^{2})(2ab^{2}))(-3a^{2}b^{2})
   (4a^{2}b^{4})(-3a^{2}b^{2})
   <u />-12a^{4}b^{6}

5.-6a^{3}(a^{2} - 2a + 1)
   -6a^{3}(a^{2}) + 6a^{3}(2a) - 6a^{3}(1)
   -6a^{5} + 12a^{4} - 6a^{3}

6.-2xy(x^{2} - 3xy + y^{2})
   -2xy(x^{2}) + 2xy(3xy) - 2xy(y^{2})
   -2x^{3}y + 6x^{2}y^{2} - 2xy^{3}

7.(a + b)(2a^{2} - ab + 3b^{2})
   (2a^{3} - a^{2}b + 3ab^{2} + 2a^{2}b - ab^{2} + 3b^{3})
   (2a^{3} - a^{2}b + 2a^{2}b + 3ab^{2} - ab^{2} + 3b^{3})
   2a^{3} + a^{2}b + 2ab^{2} + 3b^{3}
  
Reptile [31]3 years ago
4 0
1. (2cd^{3})(-2c)(3c^{d})=\\-12c^{d+2}d^{3}

2. (2x^{2})(3x^{6})-(4x^{4})(2x^{4})=\\6x^{8}-8x^{8}=\\-2x^{8}

3. (6x^{2})(3x^{6})+(4x^{4})(2x^{4})=\\18^{8}+8x^{8}=\\26x^{8}

4. (2ab^{2})^{2}(-3a^{2b^{2}})=\\4a^{2}b^{4}(-3a^{2b^{2}})=\\-12a^{2b^{2}+2}b^{4}

5. -6a^{3}(a^{2}-2a+1)=\\-6a^{5}+12a^{4}-6a^{3}

6. -2xy(x^{2}-3xy+y^{2})=\\-2x^{3}y+6x^{2}y^{2}-2xy^{3}

7. (a+b)(2a^{2}-ab+3b^{2})=\\2a^{3}-a^{2}b+3ab^{2}+2a^{2}b-ab^{2}+3b^{3}=\\2a^{3}+3b^{3}+a^{2}b+2ab^{2}
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