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2 years ago

The empty boxes are where the answers need to go. Can anyone help?

Mathematics

1 answer:

Butoxors [25]2 years ago

8 0

First two boxes...(a+c), b

second line box.....(a+c)/2

third line box ....b/2

this was a good question...a Little tricky !

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What is the vertical asymptote for this function?<br> y=1/x-2

nataly862011 [7]

Answer: x = 0

Step-by-step explanation: so x = 0 is the equation of the vertical asymptote, and 0 must be left out of the domain: (−∞,0)U(0,∞) in interval notation.

8 0

2 years ago

Factor the polynomial expression x^4+18x^2+81

Vikentia [17]

Answer:

Step-by-step explanation:

Hello,

please consider the following

$x^4+18x^2+81=(x^2)^2+2*(3^2)x^2+(3)^4\\\\=(x^2+9)^2$

hope this helps

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2 years ago

A. —————-is the number above the fraction bar in a fraction. A ———-is the number below the fraction bar that respresents the num

Step2247 [10]

Answer:

First numerator and second denominator

5 0

2 years ago

? Don't Send links, don't Write random things and get the points for free.

alekssr [168]

Answer:

$V = 1847.26\ ft^3$

Step-by-step explanation:

Step 1: Determine the volume

$V=\pi r^2h$

$V = \pi *(7\ ft)^2 * (12\ ft)$

$V = \pi *49\ ft^2 * 12\ ft$

$V = \pi * 588\ ft^3$

$V = 1847.26\ ft^3$

Answer: $V = 1847.26\ ft^3$

6 0

1 year ago

Numbered disks are placed in a box and one disk is selected at random. If there are 6 red disks numbered 1 through 6, and 2 yell

Tatiana [17]

Answer:

$\frac{3}{4}$

Step-by-step explanation:

Total number of red disk=6

Total number of yellow disk=2

Total disk=6+2=8

Odd number=1,3,5,7=4

Odd number on red disk=1,3,5=3

Probability, $P(E)=\frac{favorable\;cases}{total\;number\;of\;cases}$

Using the formula

The probability of getting odd number disk= $\frac{4}{8}=\frac{1}{2}$

The probability of getting odd numbered red disk= $\frac{3}{8}$

The probability of selecting a red disk,given that an odd numbered disk is selected= $\frac{\frac{3}{8}}{\frac{1}{2}}=\frac{3}{8}\times 2=\frac{3}{4}$

Using conditional probability

$P(A/B)=\frac{P(A\cap B)}{P(B)}$

6 0

2 years ago