Answer:
<em><u>given </u></em><em><u>:</u></em><em><u>-</u></em>
<em><u>for </u></em><em><u>rectangular</u></em><em><u> </u></em><em><u>part:</u></em><em><u> length</u></em><em><u>=</u></em><em><u>1</u></em><em><u>2</u></em><em><u>i</u></em><em><u>n</u></em><em><u>,</u></em><em><u> breadth</u></em><em><u>=</u></em><em><u>8</u></em><em><u>i</u></em><em><u>n</u></em>
<em><u>for</u></em><em><u> </u></em><em><u>triangular</u></em><em><u> </u></em><em><u>part:</u></em><em><u>base=</u></em><em><u>8</u></em><em><u>i</u></em><em><u>n</u></em><em><u>,</u></em><em><u> </u></em><em><u>height=</u></em><em><u>3</u></em><em><u>i</u></em><em><u>n</u></em>
<em><u>area of the given fig:</u></em>
<em><u>area of the given fig:area of 2 triangles +area of rectangle </u></em>
<em><u>
</u></em>
<h2>
<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> </u></em><em><u>you</u></em><em><u><</u></em><em><u>3</u></em></h2>
<h3 />
Answer:
The answer is 3.4
Step-by-step explanation:
5 or more, round up
4 or less, round down
rounding 6
round up
so...
3.4
(-2, -7) and (-4, -9)
Given that the sample size is 12, thus the degree of freedom = 12 - 1 = 11.
Using technology, the p value of the t statistic, t = 2.028 is 0.9663.
Answer: Not possible
Step-by-step explanation: A whole number is an integer or a number without fractions. Both 15% and 40% are less than 1 since they are less than 100%; therefore, it is impossible to express them as whole numbers. They can only be expressed as the mixed numbers of 0.15 and 0.4, or 15/100 and 40/100.
Answer:
95% Confidence interval for the variance:

95% Confidence interval for the standard deviation:

Step-by-step explanation:
We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².
The sample, of size n=8, has a standard deviation of s=2.89 miles.
Then, the variance of the sample is

The confidence interval for the variance is:

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

Then, the confidence interval can be calculated as:

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:
