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2 years ago

Don’t need to send the math or anything just need the answer will give brainliest!!!

Mathematics

1 answer:

STatiana [176]2 years ago

5 0

Answer:

I think the answer is C. It's increasing 5 dollars each additional hour.

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3⁷×3-⁴ I need help asap!

SCORPION-xisa [38]

Hope it helps

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8 0

1 year ago

Read 2 more answers

The image represents what geometric construction? A) Copy a triangle construction B) Copy a segment construction C) Parallel lin

Umnica [9.8K]

Answer:

d perpendicular bisected and midpoint

5 0

2 years ago

...................................................................

Genrish500 [490]

Answer:

12 cm

Step-by-step explanation:

The Pythagorean Theorem is as follows:

$a^{2} +b^{2} =c^{2}$

A and B represent the side lengths (legs) and C represents the hypotenuse.

The length of one leg equals 5cm. (This can be represented by either a or b)

The hypotenuse equals 13 cm.

Plug these into the equation from above:

$a^{2} + (5^{2}) = (13^{2})$

Solve for the other leg:

$a^{2} + 25 = 169$ Square what's in the parentheses from above

$a^{2} = 144\\$ Subtract 25 from 169

$\sqrt{a^{2} } = \sqrt{144}$ Square root both sides

a = 12 cm

Thus, the length of the other leg is 12 cm.

Let's check our answer:

$12^{2} +5^{2} =13^{2}$ Square everything

144 + 25 = 169 Add

169 = 169

Because both sides are equal it means that 12 cm is the correct answer.

Hope this helps!!

3 0

1 year ago

Which ordered pair is on the graph of the function? O (-1,2) O (6,-3) O (-2,-4) O (-6, 4)

tino4ka555 [31]

Answer:

(6, -3)

Step-by-step explanation:

7 0

2 years ago

Find the generating function for the sequence 1,1,1,2,3,4,5,6,....

marin [14]

Answer:

$P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1$ [/tex]

Step-by-step explanation:

The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

$1,1,1,2,3,4,5,6,...$

the generating function would be

$P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\$

we can multiply P(x) by x to get

$xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...$

Note that

$P(x)-xP(x)=1+(2x^3-x^3)+(3x^4-2x^4)+(4x^5-3x^5)+(5x^6-4x^6)+...\\ \\=1+x^3+x^4+x^5+x^6+...=1+x^3(1+x+x^2+x^3+x^4+...)$

which for $\mid x \mid < 1$ can be rewritten as

$(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}$

8 0

2 years ago