1: establish the angles, basically label one x (the small one) and the other y (the bigger one)
2. supplementary angles add up to 180, so therefore you have the equation x + y = 180.
3. so y (the bigger one) is 8 less than 3 times the smaller one (x) therefore you come up with the equation y = 3x - 8
4. plug in the equation of the bigger one into the other equation
x + 3x - 8 = 180
(combine like terms)
4x - 8 = 180
5. solve the equation by adding 8 to 180, then by dividing by 4.
x should equal 47
6. plug in 47 into the x + y = 180 equation, subtract 47 from 180 and you end up with 133
i hope i explained it alright
If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.
Calculation for the Amount of IV
It is given that,
1L IV contains 60meq of kcal
⇒ 1000 mL of IV contains 60meq of kcal
⇒ 1 mL of IV will contain 60 / 1000 meq of kcal
As per the question,
The amount of IV infused in the patient = 400 mL
⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)
= 4 × 6
= 24 meq of kcal
Hence, the patient receives 24meq of kcal amount of IV.
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Answer: B) False
A counter-example would be the cubic polynomial y = x^3 which doesn't have a max or a min. The graph stretches forever in both directions (up and down) indicating that the range is the set of all real numbers.