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shepuryov [24]
3 years ago
7

Celeste walked 24 and 1/2 km this week for exercise. There are 1,000 meters in 1 kilometer. How many meters did Celeste walk?​

Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0

Answer:

Step-by-step explanation:

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the distance from the park to the grocery store is 0.9 mile. Ezra runs 8 tenths of that distance and walks the rest of the way.
Sholpan [36]

The distance from the park to the grocery store is 0.9 mile. Ezra runs 8 tenths of that distance and walks the rest of the way. The distance ezra runs can be solve by multiplying 8/10 to the total distance.

X = 0.9(8/10)=0.72 mile

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HELP. EASY MATH. 14POINTS
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Do Pythagorean theorem. If you don't know what that is...

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3 years ago
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Kala takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $98 per credit
masya89 [10]

Answer:

T=98W-115W+1840

Step-by-step explanation:

$98 per credit at Westside (W)

$115 per credit at Pinewood (P)

Expression 1 : 98W+115P=T

Expression 2 : W+P=16

Combined: if W=16-P

Total=98W+115(16-W)

T=98W-115W+1840

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2 years ago
Can someone please explain how to do c i thank you
maksim [4K]

i) first you combine the like terms; 3x² and x², then 4x and -8x, then -7n and -1.

Then you would get 4x²-4x-8.

You then cannot simplify further. so your answer would be 4x²-4x-8.

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Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –23x + 1
Finger [1]

Answer:

Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 .

Step-by-step explanation:

Given as :

The equation of one line

y = - 23 x + 12

∵ The equation of line in slope-intercept form is

y = m x + c

where m is the slope of line and c is y-intercept

Now, Compare given line with standard line equation

So, The slope of given line = m = - 23

Now, Again

Other line is passing through point (6 , - 11) and is parallel to given line

so, both the lines are parallel

For parallel line condition , Slope of both lines are equal

Let The slope of other line = M

So, M = m = - 23

Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form

y - y_1 = M × (x -  x_1)

i.e y - ( - 11) = (- 23) × (x - 6)

Or, y + 11 = - 23 × x + 138

Or, y = - 23 x + 138- 11

i.e y = - 23 x + 127

So, The equation of other line  y = - 23 x + 127

Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 . Answer

8 0
3 years ago
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