Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as

n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) =
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
use the formula and evaluate the givens
Step-by-step explanation:
336=(14/11)^2 * 22/7*h
336=196/121 * 22/7h
336= 4312/847h
336= 5.09h
h=66
Answer:
g(x) = -2|x+1| -3
Step-by-step explanation:
f(x) = |x|
y = f(x) + C C < 0 moves it down
y = |x| -3 for shifting down 3
y = f(x + C) C > 0 moves it left
y = |x+1| -3 for move it left 1
y = Cf(x) C > 1 stretches it in the y-direction
y = 2|x+1| -3 to stretch it 2 vertically
y = −f(x) Reflects it about x-axis
y = -2|x+1| -3
<span>-3(2m-1)-n
First we multiply -3 to the first term of the expression
---------- > ( -3*2m + (-3)*(-1) ) - n
</span>---------- > ( -6m + 3 ) - n<span>
-----------> -6m -n + 3
Then, we divide and multiply by -6, (the expression remains the same)
</span>
---- > (-6/-6)* (-6m -n + 3)<span>
---- > -6*[m + (n/6) - 1/2]
</span>
The answer is -6*[m + (n/6) - 1/2]