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finlep [7]
3 years ago
9

Can someone please help me with this?

Mathematics
2 answers:
qwelly [4]3 years ago
5 0

Answer:

First option is the correct answer

Second option is the correct answer

Step-by-step explanation:

Five added to a number, then divides by two equals eight

\frac{x+5}{2} = 8

Three added to one fourth of a number gives seven.

\frac{1}{4} x+3= 7

swat323 years ago
4 0

Answer:

Step-by-step explanation:

1) option A

Let the number be x

Five added to a number = x +5

Then divided by 2 :    \frac{x+5}{2}

Equation:

\frac{x+5}{2}=8

2) option B

one fourth of a number: (1/4)x

Three added to one fourth of a number : \frac{1}{4}x+3

Equation:

\frac{1}{4}x+3=7

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The distance of the ship from the lighthouse can be determined using

trigonometric ratios.

  • The ship's horizontal distance from the lighthouse is approximately  <u>1,303.03 feet</u>.

Reasons:

The given parameters are;

The height of the beacon-light above the ground = 114 feet

The angle of elevation to the beacon measured by the boat crew = 5°

Required:

The horizontal distance of the ship from the lighthouse

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The beacon-light that is seen by the boat crew, the height of the beacon light, and the horizontal distance of the ship from the lighthouse form a right triangle.

Therefore, we have;

\displaystyle tan (\theta) = \mathbf{ \frac{Opposite}{Adjacent}}

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Which gives;

\displaystyle The \ ship's \ horizontal \ distance \ from \ the \ lighthouse=  \frac{Height \ of \ beacon \ light}{tan(angle \ of \ elevation)}

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\displaystyle The \ ship's \ horizontal \ distance \ from \ the \ lighthouse=  \frac{114 \ feet}{tan(5^{\circ})} \approx \mathbf{1,303.03 \ feet}

The ship's horizontal distance from the lighthouse = <u>1,303.03 feet</u>.

Learn more about angle of elevation here:

brainly.com/question/15821537

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