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2 years ago

Help pleaseeeeeeeeeee

Mathematics

1 answer:

Nostrana [21]2 years ago

7 0

Seniors have the higher hourly pay rate and seniors make more money

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A basketball has a volume of 23047 cm

Elodia [21]

Answer:

17.65693585 = r

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

23047 = 4/3 (3.14) r^3

23047 = 4.1866666666 r^3

Divide by 4.186666 on each side

23047/4.18666666 = 4.1866666666/4.18666666 *r^3

5504.856688 = r^3

Take the cubed root on each side

(5504.856688)^1/3 = r^3^(1/3)

17.65693585 = r

4 0

3 years ago

Find the volume of the cylinder. Use 3.14 for T. Round to the nearest tenth.

AleksandrR [38]

It will be 5 cm and use 3.14 to multiply

4 0

1 year ago

Please help with this algebra question

zhenek [66]

We have
-2x-3y <12
For this case what you should do is to graph the following straight line:
-2x-3y = 12
Then, the solution will be the shaded region that satisfies the following inequality:
-2x-3y <12
In the shaded region you will find all the solution points.
Answer:
See attached image

7 0

3 years ago

Find the equation of the line passing through (3,4), (-1,-2).

Kryger [21]

Answer:

(y-(-2))/(x-(-1)= (-2-4)/(-1-3)

(y+2)/(x+1)= (-6)/(-4)

(y+2)/(x+1)= (3/2)

Cross multiplying

2y+4= 3x+3

3x-2y-1=0

7 0

2 years ago

Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

6 0

2 years ago

Help pleaseeeeeeeeeee​

Help pleaseeeeeeeeeee