If Keith had 1 1/2 cups, he can't use <span>5 2/3 cups. He cant use more than what he had. There is error in this question.</span>
9514 1404 393
Answer:
3
Step-by-step explanation:
Let x represent the number. The problem statement tells you ...
2/3(3x +6) = 10
2x +4 = 10 . . . . . . use the distributive property
x +2 = 5 . . . . . . . . divide by 2
x = 3 . . . . . . . . . . .subtract 3
The number is 3.
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<em>Comment on the solution</em>
The above shows an "alternative" solution method. The more usual way this might be done is ...
2(3x +6) = 30 . . . . . multiply by 3 to clear fractions
6x +12 = 30 . . . . . . . eliminate parentheses
6x = 18 . . . . . . . . . . . subtract 12
x = 3 . . . . . . . . . . . . divide by 6
A function is a rule that relates inputs to outputs.It takes elements from the domain and relates them to the codomain. It relates each element of a set with exactly one element of another set. In the graph, we see a single element of a set being mapped to different codomain. Thus, the graph does not represent a function
This is the formula for a triangle base
b=2A
hb implement
Answer:
x = π/2 + πk
Step-by-step explanation:
cot² x csc² x + 2 csc² x − cot² x = 2
Multiply both sides by sin² x:
cot² x + 2 − cos² x = 2 sin² x
Add cos² x to both sides:
cot² x + 2 = 2 sin² x + cos² x
Pythagorean identity:
cot² x + 2 = sin² x + 1
Subtract 1 from both sides:
cot² x + 1 = sin² x
Pythagorean identity:
csc² x = sin² x
Multiply both sides by sin² x:
1 = sin⁴ x
Take the fourth root:
sin x = ±1
Solve for x:
x = π/2 + 2πk, 3π/2 + 2πk
Which simplifies to:
x = π/2 + πk
