Answer:
Check the explanation
Step-by-step explanation:
A. All polynomials of the form p(t) = a + bt2, where a and b are in: This means that A is closed under scalar mult and vector addition, and includes the zero vector.
B.All polynomials of degree exactly 4, with real coefficients: what this means is that under vector addition, B isn't closed, and it does not consist of the zero vector. What it consist of is just polynomials with degree exactly 4. Let f=x4+1f=x4+1 and let g=−x4g=−x4. Both are in B, but their sum is not, because it has degree 0.
C. All polynomials of degree at most 4, with positive coefficients: what this means is that C is not a subspace for the reason that the positive coefficients make zero vector impossible. The restriction there also makes C not closed under multiplication by the scalar −1.
So the answer is only A :D
9514 1404 393
Answer:
they are not
Step-by-step explanation:
The inverse matrix is the transpose of the cofactor matrix, divided by the determinant.
The cofactor matrix for a 2×2 matrix is ...
![\left[\begin{array}{cc}a_{22}&-a_{21}\\-a_{12}&a_{11}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da_%7B22%7D%26-a_%7B21%7D%5C%5C-a_%7B12%7D%26a_%7B11%7D%5Cend%7Barray%7D%5Cright%5D)
The transpose of this will have the off-diagonal terms swapped, so the inverse matrix is ...
![\displaystyle\frac{\left[\begin{array}{cc}a_{22}&-a_{12}\\-a_{21}&a_{11}\end{array}\right]}{a_{11}a_{22}-a_{21}a_{12}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da_%7B22%7D%26-a_%7B12%7D%5C%5C-a_%7B21%7D%26a_%7B11%7D%5Cend%7Barray%7D%5Cright%5D%7D%7Ba_%7B11%7Da_%7B22%7D-a_%7B21%7Da_%7B12%7D%7D)
We see that the second matrix is the transpose of the cofactor matrix, but the determinant is (5)(2)-(3)(4) = -2, so there has clearly been no division by the determinant. The actual inverse matrix of the first one shown is ...
![\left[\begin{array}{cc}-1&2\\1.5&-2.5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%262%5C%5C1.5%26-2.5%5Cend%7Barray%7D%5Cright%5D)
_____
You can compute the matrix product to see if you get an identity matrix. Here, the upper left term in the product is ...
(5)(2) +(4)(-3) = -2 . . . . . not 1, so the product matrix is not an identity matrix
The matrices are not inverses.
He will drink 6 5-gallon containers of juice in 30 days.
Let the second no. be x.
First no. = x+6
Third no. = 3x
Sum= 81
Therefore,
x + x + 6 + 3x = 81
=> 5x + 6 = 81
=> 5x = 81-6
=> x = 75/5
=> x = 15
Answer:
So, the first no. is (15 + 6) 21
The second no. is 15
The third no. is (3*15) 45
Hope it helps u!
okay so you wanna do
-1 times 9 = you get -9
same for 14(-2)= -28
-9 times -6 =54
so then you do -2 times 50 then you get -100
plz mark Brainliest !!!
thanks!!!