All it takes for a relation to be a function is for each possible first number of a pair there's only one possible second number.
So if any of the sets has two pairs with the same first number, that one's not a function.
The last one has (3,2) and (3,5) so isn't a function.
The solution of <span>0 = x2 − 5x − 36 is x = - 4 and x = 9
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2A)
C is correct.
2B) If x + 13 = 28, solve.

If x = 15 and x + 13 = 28, you can solve it two ways:
1. Plug x into 4x + 26 to get a perimeter of
86, or
2. Redo the equation:

3a. Since the 6z is negative, you want an expression the has 5z - (11z). Answers A and D have that in their answer.
But since the 13 is positive, you want the answer that subtracts the smaller number from the larger. Thus,
D is your answer since it subtracts 2 from 15.
3b) You think about this question the same way; 6z is positive, so the smaller number is being subtracted from the larger, meaning that 11z - 5z is what you look for. C and D are the two that have that, so now let's look at the second term.
The 13 is negative, so you want the answer that has 2 - 15. The answer that has that is
D.
Hope this helps :D
Answer:
C. 3
Step-by-step explanation:
2x+6
Divide 2 on both sides
x=3
5. The graph of g(x) is narrower. Both graphs open upward. The vertex of g(x), (0,10), is translated 10 units up from the vertex of f(x) at (0,0)
6. The graph of g(x) is wider. Both graphs open upward. The vertex of g(x), (0,-3) is translated 3 units down from the vertex of f(x) at (0,0)
7.The graph of g(x) is narrower. g(x) opens downward and f(x) opens upward. The vertex of g(x), (0,8) is translated 8 units up from the vertex of f(x) at (0,0).
8. The graph of g(x) is wider. g(x) opens downward and f(x) opens upward. The vertex of g(x), (0,1/4) is translated 1/4 units up from the vertex of f(x) at (0,0).
9. A. h1(t)=-16t^2+400 h2(t)= -16t^2+1600
9. B The graph of h2 is a vertical translation of the graph of h1 : 1200 units up.
9. C sandbag dropped from 400 ft: 5 s
sandbag dropped from 1600 ft: 10 s