Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
C, D, and E are correct
Step-by-step explanation:
p(2)= 1/6; p(3)= 1/6; p(4)= 1/6; 1/6=1/6=1/6
p(1)= 3/6; 3/6=1/2
p(4) = 1/6; There are six sections and one section is labeled<em> '4' </em>
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Hope this helped! ;p
Answer:
The scale factor is 1/2
Step-by-step explanation:
Given
and 
Required
The scale factor from
to 
Take a corresponding side in both triangles.
We have:

The scale factor from
to
is:



2/3
16/24 and divide the greatest common factor (8)