Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
Answer:
112cm
Step-by-step explanation:
4×2=8
8×2=16
4×8=32
8+16+32= 56×2= 112cm
Hope this helps!
B - 8x
To find this, combine like terms.
8x - 2x is 6x, then add the two x's on the side to bring it back to 8x.
Hope this helps!
Answer:
Step-by-step explanation:
The first digit is 9
the 2nd one from the right = 2
So far what you have is
911, 121
941,121
There seems to be a second 4 implied. What is it? I'll edit if you get it to me in the next hour.
