Answer:
The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the reading speed of a sixth-grader whose reading speed is at the 90th percentile
This is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.




The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.
Answer:
Average rate of change = 3
Step-by-step explanation:
- We know that the average rate of change is basically a measure of the slope of the secant line in the closed interval [a, b].
here a = -3 and b = 4
⇒ Average rate of change = f(b) - f(a) / b - a
= (27 - 6) / (4 - (-3))
= 21 / 7
= 3
Therefore, Average rate of change = 3
Answer:
Attached file
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given the right angled triangle, ∆BCD, you are required to find the measure of angle C.
Apply the trigonometric ratio formula to find m < C.
Adjacent side = 7
Hypotenuse = 8
Trigonometric ratio formula to apply would be:




(To nearest tenth)