Our inter-arrival time follows Poisson distribution with parameter 14 which is in hour so first we have to calculate this in minutes as we have to calculate probability in minutes.

So converting 14 into minutes will give $\frac{14}{60}$ =0.233

Let X=inter-arrival time between two customers

and here $\lambda$ = 0.233

Probability(X is less than or equal to 2 minutes) = P(X=0) + P(X=1) + P(X=2)

Now the Poisson distribution has PDF = $\frac{\exp ^{-\lambda }\times \lambda ^{X}}{X!}$

So P(X = 0) = $\frac{\exp ^{-0.233}\times 0.233^{0}}{0!}$ = 0.79215

P(X= 1) = $\frac{\exp ^{-0.233}\times 0.233^{1}}{1!}$ = 0.18457

P(X=2) = $\frac{\exp ^{-0.233}\times 0.233^{2}}{2!}$ = 0.02150

Now adding all three probability gives = 0.79215 +0.18457 + 0.02150=0.99822

3 0

3 years ago

The equations in this system were added to solve for y. What is the value of y? x + 6 y = 10. Minus x + 3 y = negative 15. Equal

zheka24 [161]

Answer:

y = -5/9

Step-by-step explanation:

Answered it by using Photo Math :)

7 0

3 years ago

A pyramid has a height of 18 centimeters and a base with an area of 26 square centimeters. Find the volume. please Help!

juin [17]

Answer:

156cm cubed

Step-by-step explanation:

i took the test...

4 0

3 years ago